मराठी

In the given figure, O is centre of the circle and angle OBA = 50°.The angle P is ______.

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प्रश्न

In the given figure, O is centre of the circle and angle OBA = 50°.
The angle P is ______.

The image displays a circle with center $O$, points $A$ and $B$ on the circumference connected by a chord, a point $P$ on the circumference, and an angle of $50^\circ$. It illustrates the central angle theorem and isosceles triangle properties within circle geometry.

पर्याय

  • 50°

  • 80°

  • 40°

  • 60°

MCQ
रिकाम्या जागा भरा
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उत्तर

In the given figure, O is centre of the circle and angle OBA = 50°.
The angle P is 40°.

Explanation: 

From figure,

In △ OAB,

OA = OB (Radius of common circle)

We know that,

Angles opposite to equal sides of a triangle are equal.

∴ ∠A = ∠B = 50°

By angle sum property of triangle,

⇒ ∠A + ∠B + ∠O = 180°

⇒ 50° + 50° + ∠O = 180°

⇒ ∠O + 100° = 180°

⇒ ∠O = 180° - 100° = 80°.

We know that,

The angle which an arc subtends at the center is double that which it subtends at any point on the remaining part of the circumference.

⇒ ∠O = 2∠P

⇒ ∠P = `(∠O)/2` = `(80°)/2`= 40°.

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पाठ 17: Circles - EXERCISE 17 (A) [पृष्ठ २५७]

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सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 17 Circles
EXERCISE 17 (A) | Q 1. (b) | पृष्ठ २५७
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