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प्रश्न
In the given figure, in ∆ABC, point D on side BC is such that, ∠BAC = ∠ADC. Prove that, CA2 = CB × CD.
सिद्धांत
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उत्तर
Given: In ΔBAC and ΔADC,
∠BAC ≅ ∠ADC ...(Given)
∠ACB ≅ ∠DCA ...(Common angle)
∴ ΔBAC ∼ ΔADC ...(AA test of similarity)
∴ `"CA"/"CD" = "CB"/"CA"` ...(Corresponding sides of similar triangles are in proportion)
∴ CA2 = CB × CD.
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