Advertisements
Advertisements
प्रश्न
In the given figure, angle ACP = ∠BDP = 90°, AC = 12 m, BD = 9 m and PA= PB = 15 m. Find:
(i) CP
(ii) PD
(iii) CD
Advertisements
उत्तर
Given : AC = 12 m
BD = 9 m
PA = PB= 15 m
(i) In right angle triangle ACP
(AP)2 = (AC)2 + (CP)2
152 = 122 + CP2
225 = 144 + CP2
225 – 144 = CP2
81 = CP
`sqrt81` = CP
∴ CP = 9 m
(ii) In right angle triangle BPD
(PB)2 = (BD)2 + (PD)2
(15)2 = (9)2 + PD2
225 = 81 + PD2
225 – 81 = PD2
144 = PD2
`sqrt144` = PD2
∴ PD = 12 m
(iii) CP = 9 m
PD = 12 m
∴ CD = CP + PD
= 9 + 12
= 21 m
APPEARS IN
संबंधित प्रश्न
PQR is a triangle right angled at P and M is a point on QR such that PM ⊥ QR. Show that PM2 = QM . MR
Identify, with reason, if the following is a Pythagorean triplet.
(11, 60, 61)
In a trapezium ABCD, seg AB || seg DC seg BD ⊥ seg AD, seg AC ⊥ seg BC, If AD = 15, BC = 15 and AB = 25. Find A(▢ABCD)
In right angle ΔABC, if ∠B = 90°, AB = 6, BC = 8, then find AC.
In the figure, given below, AD ⊥ BC.
Prove that: c2 = a2 + b2 - 2ax.
In the figure below, find the value of 'x'.
Find the Pythagorean triplet from among the following set of numbers.
2, 6, 7
Two trains leave a railway station at the same time. The first train travels due west and the second train due north. The first train travels at a speed of `(20 "km")/"hr"` and the second train travels at `(30 "km")/"hr"`. After 2 hours, what is the distance between them?
Prove that the area of the semicircle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the semicircles drawn on the other two sides of the triangle.
The longest side of a right angled triangle is called its ______.
