Advertisements
Advertisements
प्रश्न
In the adjoining figure, the circle with center D touches the sides of ∠ACB at A and B. If ∠ACB = 52°, find the measure of ∠ADB.
बेरीज
Advertisements
उत्तर
In a figure, D is the centre of the circle.
ADBC is a quadrilateral.
∴ ∠ACB + ∠CAD + ∠CBD + ∠ADB = 360° ......[The sum of all angles of a quadrilateral is 360°.]
∴ 52° + 90° + 90° + ∠ADB = 360° ......[Tangent theorem]
∴ ∠ADB + 232° = 360°
∴ ∠ADB = 360° – 232°
∴ ∠ADB = 128°
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
