Advertisements
Advertisements
प्रश्न
In how many ways 5 boys and 3 girls can be seated in a row, so that no two girls are together?
Advertisements
उत्तर
5 boys can be seated among themselves in 5P5 = 5! Ways. After this arrangement, we have to arrange the three girls in such a way that in between two girls there atleast one boy.
So the possible places girls can be placed with the × symbol given below.
× B × B × B × B × B ×
∴ There are 6 places to seated by 3 girls which can be done 6P3 ways.
∴ Total number of ways = 5! × 6P3
= 120 × (6 × 5 × 4)
= 120 × 120
= 14400
APPEARS IN
संबंधित प्रश्न
Find r if `""^5P_r = 2^6 P_(r-1)`
How many three digit numbers can be formed by using the digits 0, 1, 3, 5, 7 while each digit may be repeated any number of times?
Evaluate each of the following:
P(6, 4)
Write the number of ways in which 6 men and 5 women can dine at a round table if no two women sit together ?
How many numbers greater than 10 lacs be formed from 2, 3, 0, 3, 4, 2, 3 ?
The number of six letter words that can be formed using the letters of the word "ASSIST" in which S's alternate with other letters is
Number of all four digit numbers having different digits formed of the digits 1, 2, 3, 4 and 5 and divisible by 4 is
The number of different ways in which 8 persons can stand in a row so that between two particular persons A and B there are always two persons, is
How many strings are there using the letters of the word INTERMEDIATE, if all the vowels are together
How many words can be formed with the letters of the word MANAGEMENT by rearranging them?
