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प्रश्न
In fig. shows a snap shot of a wave from of frequency 50 Hz in a string. The numbers in the diagram represents distance in centimeters. Fpr the wave motion, find
(a) Wavelength,
(b) Amplitude,
(c) Velocity.
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उत्तर
(a) Wavelength = Distance between two successive crests or two successive troughs=10 cm
(b) Amplitude = Maximum displacement of the particles from the mean position = 4 cm
(c)
Velocity= frequency × wave length
Given, frequency = 50 Hz,
wavelength= 10 cm= 0.1 m
.·. Velocity= 50 x 0.1=5 m/s
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