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In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why? limx→31x-3

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प्रश्न

In exercise problems 7 – 15, use the graph to find the limits (if it exists). If the limit does not exist, explain why?

`lim_(x -> 3) 1/(x - 3)`

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उत्तर

To find `lim_(x -> 3) 1/(x - 3)`

y = f(x) = `1/(x - 3)`

From the graph the value of the function at x = 3 the curve does not meet the line x = 3

∴ The value of the function is not defined at the point x = 3.

Hence `lim_(x -> 3) 1/(x - 3)` does not exist at x = 3.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Differential Calculus - Limits and Continuity - Exercise 9.1 [पृष्ठ ९६]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 9 Differential Calculus - Limits and Continuity
Exercise 9.1 | Q 11 | पृष्ठ ९६

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