Advertisements
Advertisements
प्रश्न
Find the value of 'a': 4x2 + ax + 9 = (2x + 3)2
Advertisements
उत्तर
4x2 + ax + 9 = (2x + 3)2
Comparing coefficients of x terms, we get
ax = 12x
so, a = 12
APPEARS IN
संबंधित प्रश्न
Expand : `( 3a + 2/b )( 2a - 3/b )`
Expand : ( 5x - 3y - 2 )2
Expand : `( x - 1/x + 5)^2`
In the expansion of (2x2 - 8) (x - 4)2; find the value of coefficient of x3.
In the expansion of (2x2 - 8) (x - 4)2; find the value of coefficient of x2
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If a2 + b2 = 34 and ab = 12; find : 7(a - b)2 - 2(a + b)2
The difference between two positive numbers is 4 and the difference between their cubes is 316.
Find : The sum of their squares
Find the value of 'a': 4x2 + ax + 9 = (2x - 3)2
The sum of two numbers is 7 and the sum of their cubes is 133, find the sum of their square.
