Advertisements
Advertisements
प्रश्न
In ΔABC, AD is a median. The perpendiculars from B and C meet the line AD produced at X and Y. Prove that BX = CY.
Advertisements
उत्तर
In ΔBXD and ΔCYD
∠BXD = ∠CYD ...(90)
∠XDB = ∠YDC ...(vertically opposite angles)
BD = DC ...(AD is median on BC)
Therefore, ΔBXD ≅ ΔCYD ...(AAS criteria)
Hence, BX = CY.
APPEARS IN
संबंधित प्रश्न
Complete the congruence statement:
ΔBCA ≅?
ΔQRS ≅?
In Fig. 10.22, the sides BA and CA have been produced such that: BA = AD and CA = AE.
Prove that segment DE || BC.
In a ΔABC, if AB = AC and ∠B = 70°, find ∠A.
The following figure shown a triangle ABC in which AB = AC. M is a point on AB and N is a point on AC such that BM = CN.
Prove that:
State, whether the pairs of triangles given in the following figures are congruent or not:
In the given figure, prove that: ∆ ABD ≅ ∆ ACD
Prove that:
(i) ∆ ABC ≅ ∆ ADC
(ii) ∠B = ∠D
In ΔABC, AB = AC. D is a point in the interior of the triangle such that ∠DBC = ∠DCB. Prove that AD bisects ∠BAC of ΔABC.
Two right-angled triangles ABC and ADC have the same base AC. If BC = DC, prove that AC bisects ∠BCD.
The top and bottom faces of a kaleidoscope are congruent.
