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प्रश्न
In ΔABC, ∠A – ∠B = 24° and ∠B – ∠C = 30°. Find angle A.
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उत्तर
Given:
- △ABC
- ∠A – ∠B = 24°
- ∠B – ∠C = 30°
We need to find ∠A.
Step 1: Express the angles in terms of one variable
Let:
- ∠A = x
- ∠B = y
- ∠C = z
From the given information, we can set up the following equations:
- x – y = 24 ...(Equation 1: ∠A – ∠B = 24°)
- y – z = 30 ...(Equation 2: ∠B – ∠C = 30°)
Step 2: Use the fact that the sum of angles in a triangle is 180°
In any triangle, the sum of the interior angles is always 180°.
Therefore: ∠A + ∠B + ∠C = 180°
Substitute the variables for the angles:
x + y + z = 180° ...(Equation 3)
Step 3: Solve the system of equations
From Equation 1, we have:
x = y + 24
From Equation 2, we have:
y = z + 30
Substitute y = z + 30 into the expression for x:
x = (z + 30) + 24 = z + 54
Now, substitute x = z + 54 and y = z + 30 into Equation 3:
(z + 54) + (z + 30) + z = 180
Simplify the equation:
3z + 84 = 180
Subtract 84 from both sides:
3z = 96
Now, divide by 3:
z = 32°
Step 4: Find ∠A
Now that we know z = 32°, we can substitute this back into the equation for x:
x = z + 54
= 32 + 54
= 86°
Thus, ∠A = 86°.
