Advertisements
Advertisements
प्रश्न
In a two-digit number, the ten’s digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number.
Advertisements
उत्तर
Given, the difference between the two digits is 6 and the ten’s digit is bigger than the unit’s digit.
So, let the unit’s digit be x and ten’s digit be (x + 6).
From the given condition, we have:
x(x + 6) = 27
x2 + 6x – 27 = 0
x2 + 9x – 3x – 27 = 0
x(x + 9) – 3(x + 9) = 0
(x + 9)(x – 3) = 0
x = –9, 3
Since, the digits of a number cannot be negative.
So, x = 3.
Unit’s digit = 3
Ten’s digit = 9
Thus, the number is 93.
संबंधित प्रश्न
Find the two natural numbers which differ by 5 and the sum of whose squares is 97.
Divide 15 into two parts such that the sum of their reciprocals is `3/10`.
The denominator of a positive fraction is one more than twice the numerator. If the sum of the fraction and its reciprocal is 2.9; find the fraction.
Out of three consecutive positive integers, the middle number is p. If three times the square of the largest is greater than the sum of the squares of the other two numbers by 67; calculate the value of p.
The product of the digits of a two digit number is 24. If its unit’s digit exceeds twice its ten’s digit by 2; find the number.
The sum S of first n even natural numbers is given by the relation S = n(n + 1). Find n, if the sum is 420.
Given that the sum of the squares of the first seven natural numbers is 140, then their mean is ______.
The sum of a number and its reciprocal is 5.2. The number is ______.
The sum of the squares of two consecutive integers is 41. The integers are ______.
The product of two whole numbers, each greater than 4, is 35; the numbers are ______.
