Advertisements
Advertisements
प्रश्न
In a two-digit number, the ten’s digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number.
Advertisements
उत्तर
Given, the difference between the two digits is 6 and the ten’s digit is bigger than the unit’s digit.
So, let the unit’s digit be x and ten’s digit be (x + 6).
From the given condition, we have:
x(x + 6) = 27
x2 + 6x – 27 = 0
x2 + 9x – 3x – 27 = 0
x(x + 9) – 3(x + 9) = 0
(x + 9)(x – 3) = 0
x = –9, 3
Since, the digits of a number cannot be negative.
So, x = 3.
Unit’s digit = 3
Ten’s digit = 9
Thus, the number is 93.
संबंधित प्रश्न
A positive number is divided into two parts such that the sum of the squares of the two parts is 20. The square of the larger part is 8 times the smaller part. Taking x as the smaller part of the two parts, find the number.
The sum of a number and its reciprocal is 4.25. Find the number.
The denominator of a positive fraction is one more than twice the numerator. If the sum of the fraction and its reciprocal is 2.9; find the fraction.
Three consecutive natural numbers are such that the square of the middle number exceeds the difference of the squares of the other two by 60. Assume the middle number to be x and form a quadratic equation satisfying the above statement. Hence; find the three numbers.
The sum S of first n even natural numbers is given by the relation S = n(n + 1). Find n, if the sum is 420.
The product of two consecutive even whole numbers is 24, the numbers are ______.
The sum of a number and its reciprocal is 5.2. The number is ______.
The sum of the squares of two consecutive integers is 41. The integers are ______.
The sum of a number and its reciprocal is 4.25; the number is ______.
The sum of two whole numbers is 18 and their product is 45, the numbers are ______.
