मराठी

If Y = Sec − 1 ( X + 1 X − 1 ) + Sin − 1 ( X − 1 X + 1 ) Then Write the Value of D Y D X ? - Mathematics

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प्रश्न

If \[y = \sec^{- 1} \left( \frac{x + 1}{x - 1} \right) + \sin^{- 1} \left( \frac{x - 1}{x + 1} \right)\] then write the value of \[\frac{dy}{dx} \] ?

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उत्तर

\[\text{ We have, y } = \sec^{- 1} \left( \frac{x + 1}{x - 1} \right) + \sin^{- 1} \left( \frac{x - 1}{x + 1} \right) \]

\[ \Rightarrow y = \cos^{- 1} \left( \frac{x - 1}{x + 1} \right) + \sin^{- 1} \left( \frac{x - 1}{x + 1} \right) ........\left[ \because \sec^{- 1} x = \cos^{- 1} \left( \frac{1}{x} \right) \right]\]

\[ \Rightarrow y = \frac{\pi}{2} ..........\left[ \because \sin^{- 1} x + \cos^{- 1} x = \frac{\pi}{2} \right]\]

\[\Rightarrow \frac{dy}{dx} = 0\]

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पाठ 11: Differentiation - Exercise 11.09 [पृष्ठ ११८]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 11 Differentiation
Exercise 11.09 | Q 21 | पृष्ठ ११८

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