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If Y = Ex Cos X, Prove that D 2 Y D X 2 = 2 E X Cos ( X + π 2 ) ? - Mathematics

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प्रश्न

If y = ex cos x, prove that \[\frac{d^2 y}{d x^2} = 2 e^x \cos \left( x + \frac{\pi}{2} \right)\] ?

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उत्तर

\[y = e^x \cos x \]
\[\text { Differentiating w . r . t . x, we get }\]
\[\frac{d y}{d x} = e^x \cos x - e^x \sin x = e^x \left( \cos x - \sin x \right)\]
\[\text { Differentiating again w . r . t . x, we get }\]
\[\frac{d^2 y}{d x^2} = e^x \left( \cos x - \sin x \right) + e^x \left( - \sin x - \cos x \right)\]
\[ = e^x \cos x - e^x \sin x - e^x \sin x - e^x \cos x\]
\[ = - 2 e^x \sin x\]
\[ = 2 e^x \cos\left( x + \frac{\pi}{2} \right) \]

Hence proved.

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पाठ 12: Higher Order Derivatives - Exercise 12.1 [पृष्ठ १६]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 12 Higher Order Derivatives
Exercise 12.1 | Q 10 | पृष्ठ १६

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