मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

If y = e^ax, then x * dy/dx = ______. - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

If y = `e^ax`, then `x * dy/dx` = ______.

रिकाम्या जागा भरा
Advertisements

उत्तर

If y = `e^ax`, then `x * dy/dx =` axy.

Explanation:

y = `e^ax`

Differentiating both sides w.r.t. x, we get

`dy/dx = e^ax * d/dx (ax)`

`= e^ax * (a)`

`= a * e^ax`

∴ `dy/dx` = ay

∴ `x dy/dx = axy`

shaalaa.com
The Concept of Derivative - Derivatives of Logarithmic Functions
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Differentiation - MISCELLANEOUS EXERCISE - 3 [पृष्ठ १००]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 3 Differentiation
MISCELLANEOUS EXERCISE - 3 | Q II] 8) | पृष्ठ १००

संबंधित प्रश्‍न

Find `"dy"/"dx"`if, y = `"x"^("e"^"x")`


Find `"dy"/"dx"`if, y = `"e"^("x"^"x")`


Find `"dy"/"dx"`if, y = (2x + 5)x 


Find `"dy"/"dx"`if, y = `root(3)(("3x" - 1)/(("2x + 3")(5 - "x")^2))`


Find `"dy"/"dx"`if, y = `(log "x"^"x") + "x"^(log "x")`


Fill in the Blank

If 0 = log(xy) + a, then `"dy"/"dx" =  (-"y")/square`


State whether the following is True or False:

If y = log x, then `"dy"/"dx" = 1/"x"`


The derivative of ax is ax log a.


Find `"dy"/"dx"` if y = `sqrt(((3"x" - 4)^3)/(("x + 1")^4("x + 2")))`


If u = 5x and v = log x, then `("du")/("dv")` is ______


If u = ex and v = loge x, then `("du")/("dv")` is ______


State whether the following statement is True or False:

If y = log(log x), then `("d"y)/("d"x)` = logx


State whether the following statement is True or False:

If y = 4x, then `("d"y)/("d"x)` = 4x  


Find `("d"y)/("d"x)`, if y = [log(log(logx))]2 


Find `("d"y)/("d"x)`, if x = `sqrt(1 + "u"^2)`, y = log(1 +u2)


Find `("d"y)/("d"x)`, if y = `x^(x^x)`


Find `("d"y)/("d"x)`, if y = x(x) + 20(x) 

Solution: Let y = x(x) + 20(x) 

Let u = `x^square` and v = `square^x`

∴ y = u + v

Diff. w.r.to x, we get

`("d"y)/("d"x) = square/("d"x) + "dv"/square`   .....(i)

Now, u = xx

Taking log on both sides, we get

log u = x × log x

Diff. w.r.to x,

`1/"u"*"du"/("d"x) = x xx 1/square + log x xx square`

∴ `"du"/("d"x)` = u(1 + log x)

∴ `"du"/("d"x) = x^x (1 +  square)`    .....(ii)

Now, v = 20x

Diff.w.r.to x, we get

`"dv"/("d"x") = 20^square*log(20)`     .....(iii)

Substituting equations (ii) and (iii) in equation (i), we get

`("d"y)/("d"x)` = xx(1 + log x) + 20x.log(20)


Solve the following differential equations:

x2ydx – (x3 – y3)dy = 0


`int 1/(4x^2 - 1) dx` = ______.


FInd `dy/dx` if,`x=e^(3t), y=e^sqrtt`


Find `dy/dx` if, y = `x^(e^x)`


Find `dy/dx if, y =  x^(e^x)`


Find `dy/dx "if", y = x^(e^x)`


Find `dy/dx` if, `y = x^(e^x)`


Find `dy/(dx)  "if", y = x^(e^(x))` 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×