Advertisements
Advertisements
प्रश्न
If x3 + y3 = 9 and x + y = 3, find xy.
बेरीज
Advertisements
उत्तर
x3 + y3 = 9, x + y = 3
(x + y)3 = x3 + y3 + 3xy (x + y)
⇒ (3)3 = 9 + 3xy (3)
⇒ 27 = 9 + 9xy
⇒ 9xy = 27 - 9 = 18
⇒ xy = 2.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
If `a^2 + 1/a^2` = 18; a ≠ 0 find :
(i) `a - 1/a`
(ii) `a^3 - 1/a^3`
If `a + 1/a` = p and a ≠ 0; then show that:
`a^3 + 1/a^3 = p(p^2 - 3)`
If a ≠ 0 and `a - 1/a` = 4; find: `(a^2 + 1/a^2)`
Find the cube of: `(2"m")/(3"n") + (3"n")/(2"m")`
If a + b = 5 and ab = 2, find a3 + b3.
If p - q = -1 and pq = -12, find p3 - q3
If m - n = -2 and m3 - n3 = -26, find mn.
Evaluate the following :
(5.45)3 + (3.55)3
Expand: `[x + 1/y]^3`
Expand (52)3
