Advertisements
Advertisements
प्रश्न
If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ?
पर्याय
−6
−7
−8
11
Advertisements
उत्तर
11
Explanation;
Hint:
p(x) = x3 + 6x2 + kx + 6
Given p(−2) = 0
(−2)3 + 6(−2)2 + k(−2) + 6 = 0
−8 + 24 – 2k + 6 = 0
22 – 2k = 0
k = `22/2`
= 11
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x.
Find the remainder when x4 + 1 is divided by x + 1.
Using the Remainder Theorem, factorise the following completely:
2x3 + x2 – 13x + 6
Find the value of ‘m’, if mx3 + 2x2 – 3 and x2 – mx + 4 leave the same remainder when each is divided by x – 2.
The polynomial f(x) = ax4 + x3 + bx2 - 4x + c has (x + 1), (x-2) and (2x - 1) as its factors. Find the values of a,b,c, and remaining factor.
Find the value of p if the division of px3 + 9x2 + 4x - 10 by (x + 3) leaves the remainder 5.
(x – 2) is a factor of the expression x3 + ax2 + bx + 6. When this expression is divided by (x – 3), it leaves the remainder 3. Find the values of a and b.
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by x – 2
Determine which of the following polynomials has x – 2 a factor:
4x2 + x – 2
The remainder, when x3 – x2 + x – 1 is divided by x + 1, is ______.
