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प्रश्न
If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ?
पर्याय
−6
−7
−8
11
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उत्तर
11
Explanation;
Hint:
p(x) = x3 + 6x2 + kx + 6
Given p(−2) = 0
(−2)3 + 6(−2)2 + k(−2) + 6 = 0
−8 + 24 – 2k + 6 = 0
22 – 2k = 0
k = `22/2`
= 11
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