Advertisements
Advertisements
प्रश्न
If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ?
पर्याय
−6
−7
−8
11
Advertisements
उत्तर
11
Explanation;
Hint:
p(x) = x3 + 6x2 + kx + 6
Given p(−2) = 0
(−2)3 + 6(−2)2 + k(−2) + 6 = 0
−8 + 24 – 2k + 6 = 0
22 – 2k = 0
k = `22/2`
= 11
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by `x - 1/2`
Find 'a' if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leaves the same remainder when divided by x + 3.
The polynomials 2x3 – 7x2 + ax – 6 and x3 – 8x2 + (2a + 1)x – 16 leaves the same remainder when divided by x – 2. Find the value of ‘a’.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(x2 − 7x + 9) ; (x + 1)
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(2x3 − 2x2 + ax − a) ; (x − a)
Find the values of a and b when the polynomials f(x)= 2x2 -5x +a and g(x)= 2x2 + 5x +b both have a factor (2x+1).
Using the Remainder Theorem, factorise completely the following polynomial:
3x2 + 2x2 – 19x + 6
(x – 2) is a factor of the expression x3 + ax2 + bx + 6. When this expression is divided by (x – 3), it leaves the remainder 3. Find the values of a and b.
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 2x2 – 4x – 1; g(x) = x + 1
A polynomial in ‘x’ is divided by (x – a) and for (x – a) to be a factor of this polynomial, the remainder should be ______.
