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प्रश्न
If x = cos t sin 2t and y = sin t cos 2t, then at t = `pi/4`, the value of `dy/dx` is equal to ______
पर्याय
-2
2
`1/2`
`-1/2`
MCQ
रिकाम्या जागा भरा
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उत्तर
If x = cos t sin 2t and y = sin t cos 2t, then at t = `pi/4`, the value of `dy/dx` is equal to 2.
Explanation:
x = cos t sin 2t and y = sin t cos 2t
∴ `dx/dt` = 2cos t cos 2t - sin t sin 2t and
`dy/dt` = cos t cos 2t - 2sin t sin 2t
∴ `dy/dx = (dy/dt)/(dx/dt) = (cos t cos 2t - 2sin t sin 2t)/(2cos t cos 2t - sint sin 2t)`
∴ `(dy/dx)_{(t = pi/4)} = (0 - 2 xx 1/sqrt2)/(0 - 1/sqrt2) = 2`
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Derivative of Composite Functions
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