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प्रश्न
If `x = 2 + sqrt(3)`, find `x^2 + 1/x^2`.
बेरीज
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उत्तर
Given: `x = 2 + sqrt(3)`
We want to find: `x^2 + 1/x^2`
Stepwise calculation:
1. First, find `1/x`:
`1/x = 1/(2 + sqrt(3))` ...(By rationalizing the denominator)
`1/x = 2 - sqrt(3)`
2. Calculate `(x + 1/x)`:
`x + 1/x = (2 + sqrt(3)) + (2 - sqrt(3))`
`x + 1/x = 4`
3. Use the identity:
`(x + 1/x)^2 = x^2 + 2 + 1/x^2`
`4^2 = x^2 + 2 + 1/x^2`
⇒ `16 = x^2 + 1/x^2 + 2`
4. Therefore, `x^2 + 1/x^2`
= 16 – 2
= 14
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Rational and Irrational Numbers - Exercise 1E [पृष्ठ ३२]
