Advertisements
Advertisements
प्रश्न
If the supply function for a product is p = 3x + 5x2. Find the producer’s surplus when x = 4
Advertisements
उत्तर
The supply function p = 3x + 5x²
When x = 4
⇒ p = 3(4) + 5(4)²
p = 12 + 5(16)
= 12 + 80
p = 92
∴ x0 = 4 and p0 = 92
Producer’s Surplus
P.S = `x_0"p"_0 - int_0^(x_0) "g"(x) "d"x`
= `(4)(92) - int_0^4 (3x + 5x^2) "d"x`
= `368 - [(3x^2)/2 + (5x^3)/3]_0^4`
= `368 - {(3/2 (4)^2 + 5/3 (4)^3) - [0]}`
= `368 - {3/2 (16) + 5/3 (64)}`
= `368 - [24 + 320/3]`
= `368 - 24 - 320/3`
= `344 - 320/3`
= `(1032 - 320)/3`
= `712/3`
= `237.3`
∴PS = 237.3 units
APPEARS IN
संबंधित प्रश्न
The marginal revenue (in thousands of Rupees) functions for a particular commodity is `5 + 3"e"^(- 003x)` where x denotes the number of units sold. Determine the total revenue from the sale of 100 units. (Given e–3 = 0.05 approximately)
A firm’s marginal revenue function is MR = `20"e"^((-x)/10) (1 - x/10)`. Find the corresponding demand function
If MR = 20 – 5x + 3x2, Find total revenue function
The demand function for a commodity is p = e–x .Find the consumer’s surplus when p = 0.5
Find the consumer’s surplus and producer’s surplus for the demand function pd = 25 – 3x and supply function ps = 5 + 2x
Choose the correct alternative:
If the marginal revenue function of a firm is MR = `"e"^((-x)/10)`, then revenue is
Choose the correct alternative:
When x0 = 5 and p0 = 3 the consumer’s surplus for the demand function pd = 28 – x2 is
Choose the correct alternative:
The marginal cost function is MC = `100sqrt(x)`. find AC given that TC = 0 when the output is zero is
Choose the correct alternative:
If MR and MC denote the marginal revenue and marginal cost and MR – MC = 36x – 3x2 – 81, then the maximum profit at x is equal to
A company requires f(x) number of hours to produce 500 units. It is represented by f(x) = 1800x–0.4. Find out the number of hours required to produce additional 400 units. [(900)0.6 = 59.22, (500)0.6 = 41.63]
