Question

If the distance between the points A(4, p) and B(1, 0) is 5 units, then the value(s) of p is ______.

पर्याय

• 4 only

• – 4 only

• ± 4

• 0

Answer 1

If the distance between the points A(4, p) and B(1, 0) is 5 units, then the value(s) of p is ± 4.

Explanation:

Given, points are A(4, p) and B(1, 0).

∵ `d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

∴ `5 = sqrt((1 - 4)^2 + (0 - p)^2`

⇒ 25 = 9 + p²

⇒ p² = 25 – 9

⇒ p² = 16

⇒ p² = ± 4