मराठी

If the coefficients of x7 and x8 in 2+xn3 are equal, then n is ______.

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प्रश्न

If the coefficients of x7 and x8 in `2 + x^n/3` are equal, then n is ______.

पर्याय

  • 56

  • 55

  • 45

  • 15

MCQ
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उत्तर

If the coefficients of x7 and x8 in `2 + x^"n"/3` are equal, then n is 55.

Explanation:

Since `"T"_("r" + 1) = ""^"n""C"_"r"  "a"^("n" - "r")  x^"r"` in expansion of (a + x)n

Therefore, T8 = `""^"n""C"_7 (2)^("n" - 7)  (x/3)^7`

= `""^"n""C"_7  (2^("n" - 7))/3^7  x^7`

And T9 = `""^"n""C"_8  (2)^("n" - 8)  (x/3)^8`

= `""^"n""C"_8  (2^("n" - 8))/3^8  x^8`

Therefore, `""^"n""C"_7  (2^("n" - 7))/3^7`

= `""^"n""C"_8 (2^("n" - 8))/3^8`   ....(Since it is given that coefficient of x7 = coefficient x8)

⇒ `"n"/((7)("n" - 7)) xx (8("n" - 8))/"n" = (2^("n" - 8))/3^8 * 3^7/(2^("n" - 7))`

⇒ `8/("n" - 7) = 1/6`

⇒ n = 55

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पाठ 8: Binomial Theorem - Solved Examples [पृष्ठ १३९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 8 Binomial Theorem
Solved Examples | Q 17 | पृष्ठ १३९

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