मराठी

Expand the expression: (2x – 3)6 - Mathematics

Advertisements
Advertisements

प्रश्न

Expand the expression: (2x – 3)6

बेरीज
Advertisements

उत्तर

By using Binomial Theorem, the expression (2x – 3)can be expanded as

`(2x - 3)^6 = (2x)^6 +  ^6C_1 (2x)^5 (-  3) +  ^6C_2 (2x)^4 (-3)^2 +  ^6C_3 (2x)^3 (-  3)^3  +  ^6C_4 (2x)^2 (-  3)^4  + ^6C_5 (2x)^1  (-  3)^5  + (-  3)^6`

= `64x^6 + 6.32x^2 (-3) + 15. 16x^4 . 9 + 20.8 x^3 (- 27) + 15.4x^2 . 81 + 6.2x (-  243) + 729`

= `64x^6 - 576x^5 + 2160  x^4 - 4320x^2 + 4860x^2  - 2916x  + 729`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Binomial Theorem - Exercise 8.1 [पृष्ठ १६६]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 8 Binomial Theorem
Exercise 8.1 | Q 3 | पृष्ठ १६६

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Expand the expression (1– 2x)5


Using Binomial Theorem, evaluate of the following:
(102)5


Using binomial theorem, evaluate the following:

(99)5


Find (a + b)4 – (a – b)4. Hence, evaluate `(sqrt3 + sqrt2)^4 - (sqrt3 - sqrt2)^4`


Find ab and n in the expansion of (a + b)n if the first three terms of the expansion are 729, 7290 and 30375, respectively.


Find a if the coefficients of x2 and x3 in the expansion of (3 + ax)9 are equal.


Find the coefficient of x5 in the product (1 + 2x)6 (1 – x)7 using binomial theorem.


Evaluate `(sqrt3 + sqrt2)^6 - (sqrt3 - sqrt2)^6`


Find an approximation of (0.99)5 using the first three terms of its expansion.


Expand using Binomial Theorem `(1+ x/2 - 2/x)^4, x != 0`


Using binomial theorem determine which number is larger (1.2)4000 or 800?

 

Find the value of (1.01)10 + (1 − 0.01)10 correct to 7 places of decimal.

 

Find the rth term in the expansion of `(x + 1/x)^(2r)`


Expand the following (1 – x + x2)4 


Find the 4th term from the end in the expansion of `(x^3/2 - 2/x^2)^9`


Find the coefficient of x11 in the expansion of `(x^3 - 2/x^2)^12`


Show that `2^(4n + 4) - 15n - 16`, where n ∈ N is divisible by 225.


If n is a positive integer, find the coefficient of x–1 in the expansion of `(1 + x)^2 (1 + 1/x)^n`


Which of the following is larger? 9950 + 10050  or 10150


Find the coefficient of x50 after simplifying and collecting the like terms in the expansion of (1 + x)1000 + x(1 + x)999 + x2(1 + x)998 + ... + x1000 .


The total number of terms in the expansion of (x + a)51 – (x – a)51 after simplification is ______.


If the coefficients of x7 and x8 in `2 + x^n/3` are equal, then n is ______.


If (1 – x + x2)n = a0 + a1 x + a2 x2 + ... + a2n x2n , then a0 + a2 + a4 + ... + a2n equals ______.


The coefficient of xp and xq (p and q are positive integers) in the expansion of (1 + x)p + q are ______.


The number of terms in the expansion of (a + b + c)n, where n ∈ N is ______.


If z = `sqrt(3)/2 + i^5/2 + sqrt(3)/2 - i^5/2`, then ______.


Find the coefficient of x in the expansion of (1 – 3x + 7x2)(1 – x)16.


Find the sixth term of the expansion `(y^(1/2) + x^(1/3))^"n"`, if the binomial coefficient of the third term from the end is 45.


If the coefficient of second, third and fourth terms in the expansion of (1 + x)2n are in A.P. Show that 2n2 – 9n + 7 = 0.


In the expansion of (x + a)n if the sum of odd terms is denoted by O and the sum of even term by E. Then prove that 4OE = (x + a)2n – (x – a)2n 


Given the integers r > 1, n > 2, and coefficients of (3r)th and (r + 2)nd terms in the binomial expansion of (1 + x)2n are equal, then ______.


The number of terms in the expansion of (x + y + z)n ______.


The sum of the last eight coefficients in the expansion of (1 + x)16 is equal to ______.


If the coefficients of (2r + 4)th, (r – 2)th terms in the expansion of (1 + x)18 are equal, then r is ______.


Let `(5 + 2sqrt(6))^n` = p + f where n∈N and p∈N and 0 < f < 1 then the value of f2 – f + pf – p is ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×