Advertisements
Advertisements
प्रश्न
If the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is
पर्याय
90°
180°
270°
360°
Advertisements
उत्तर
n the given ΔABC, all the three sides of the triangle are produced. We need to find the sum of the three exterior angles so produced.

Now, according to the angle sum property of the triangle
∠A + ∠B + ∠C = 180° .......(1)
Further, using the property, “an exterior angle of the triangle is equal to the sum of two opposite interior angles”, we get,
ext.∠C = ∠A + ∠B ......(2)
Similarly,
ext.∠A = ∠C + ∠B .......(3)
Also,
ext.∠B = ∠C+ ∠A .......(4)
Adding (2) (3) and (4)
We get,
ext.∠A + ext.∠B+ ext.∠C = ∠C+∠B +∠C +∠A + ∠B + ∠A
= 2(∠A= ∠B+ ∠C )
= 2 (180°)
= 360°
Thus, ext. ∠A + ext. ∠B ext.∠C = 360°
APPEARS IN
संबंधित प्रश्न
If the bisectors of the base angles of a triangle enclose an angle of 135°, prove that the triangle is a right triangle.
In a ΔABC, ∠ABC = ∠ACB and the bisectors of ∠ABC and ∠ACB intersect at O such that ∠BOC = 120°. Show that ∠A = ∠B = ∠C = 60°.
Can a triangle have All angles equal to 60°? Justify your answer in case.
Fill in the blank to make the following statement true:
Sum of the angles of a triangle is ....
Fill in the blank to make the following statement true:
A triangles cannot have more than ......obtuse angles.
In a Δ ABC, the internal bisectors of ∠B and ∠C meet at P and the external bisectors of ∠B and ∠C meet at Q, Prove that ∠BPC + ∠BQC = 180°.
In the given figure, if AB || CD, EF || BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.

Find, giving a reason, the unknown marked angles, in a triangle drawn below:

The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
12 cm, 12 cm, 16 cm
Find all the three angles of the ΔABC
