मराठी

If the Points P (X , Y) is Point Equidistant from the Points a (5,1)And B ( -1,5) , Prove that 3x=2y - Mathematics

Advertisements
Advertisements

प्रश्न

If the points p (x , y) is point equidistant from the points A (5,1)and B ( -1,5) , Prove that 3x=2y

Advertisements

उत्तर

As per the question, we have

AP = BP

`⇒ sqrt((x -5)^2 +(y-1)^2) = sqrt((x+1)^2 +(y-5)^2)`

`⇒(x-5)^2 +(y-1)^2 = (x+1)^2 +(y-5)^2`          (Squaring both sides) 

`⇒x^2 - 10x +25 + y^2 -2y +1 = x^2 +2x +1+y^2 -10y+25`

⇒ - 10x -2y =2x-10y

⇒ 8y = 12x

⇒3x=2y

Hence, 3x=2y.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 16: Coordinate Geomentry - Exercises 1

APPEARS IN

आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 16 Coordinate Geomentry
Exercises 1 | Q 11

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

On which axis do the following points lie?

P(5, 0)


On which axis do the following points lie?

S(0,5)


The base PQ of two equilateral triangles PQR and PQR' with side 2a lies along y-axis such that the mid-point of PQ is at the origin. Find the coordinates of the vertices R and R' of the triangles.


If the points A (a, -11), B (5, b), C (2, 15) and D (1, 1) are the vertices of a parallelogram ABCD, find the values of a and b.


Find the coordinates of the circumcentre of a triangle whose vertices are (–3, 1), (0, –2) and (1, 3).


The ordinate of any point on x-axis is


Show that the points (−4, −1), (−2, −4) (4, 0) and (2, 3) are the vertices points of a rectangle.


Show that ΔABC, where A(–2, 0), B(2, 0), C(0, 2) and ΔPQR where P(–4, 0), Q(4, 0), R(0, 2) are similar triangles.


Find the area of a parallelogram ABCD if three of its vertices are A(2, 4), B(2 + \[\sqrt{3}\] , 5) and C(2, 6).                 

 


If  \[D\left( - \frac{1}{5}, \frac{5}{2} \right), E(7, 3) \text{ and }  F\left( \frac{7}{2}, \frac{7}{2} \right)\]  are the mid-points of sides of  \[∆ ABC\] ,  find the area of  \[∆ ABC\] .


If points Q and reflections of point P (−3, 4) in X and Y axes respectively, what is QR?

 

Find the distance between the points \[\left( - \frac{8}{5}, 2 \right)\]  and \[\left( \frac{2}{5}, 2 \right)\] . 

 
 
 
 

If P (x, 6) is the mid-point of the line segment joining A (6, 5) and B (4, y), find y.

 

If the centroid of the triangle formed by (7, x) (y, −6) and (9, 10) is at (6, 3), then (x, y) =


The distance of the point (4, 7) from the y-axis is


The coordinates of a point on x-axis which lies on the perpendicular bisector of the line segment joining the points (7, 6) and (−3, 4) are


Abscissa of all the points on the x-axis is ______.


The points whose abscissa and ordinate have different signs will lie in ______.


If the points P(1, 2), Q(0, 0) and R(x, y) are collinear, then find the relation between x and y.

Given points are P(1, 2), Q(0, 0) and R(x, y).

The given points are collinear, so the area of the triangle formed by them is `square`.

∴ `1/2 |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)| = square`

`1/2 |1(square) + 0(square) + x(square)| = square`

`square + square + square` = 0

`square + square` = 0

`square = square`

Hence, the relation between x and y is `square`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×