Advertisements
Advertisements
प्रश्न
If (n+2)! = 60[(n–1)!], find n
Advertisements
उत्तर
Given that (n + 2)! = 60(n – 1)!
(n + 2) (n + 1) n (n – 1)! = 60(n – 1)!
Cancelling (n – 1)! we get,
(n + 2)(n + 1)n = 60
(n + 2)(n + 1)n = 5 × 4 × 3
Both sides we consecutive product of integers
∴ n = 3
APPEARS IN
संबंधित प्रश्न
Compute `(8!)/(6! xx 2!)`
Find r if `""^5P_r = 2^6 P_(r-1)`
Find r if `""^5P_r = 2^6 P_(r-1)`
In how many of the distinct permutations of the letters in MISSISSIPPI do the four I’s not come together?
In how many ways 4 women draw water from 4 taps, if no tap remains unused?
Write the number of arrangements of the letters of the word BANANA in which two N's come together.
The number of words from the letters of the word 'BHARAT' in which B and H will never come together, is
The number of ways to arrange the letters of the word CHEESE are
Evaluate `("n"!)/("r"!("n" - "r")!)` when n = 5 and r = 2.
A coin is tossed 8 times, how many different sequences containing six heads and two tails are possible?
