मराठी

If ω is a complex cube root of unity, show that ((a + bomega + comega^2))/("c" + aomega + bomega^2) = omega^2

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प्रश्न

If ω is a complex cube root of unity, show that `((a + bomega + comega^2))/("c" + aomega + bomega^2) = omega^2`.

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उत्तर

ω is a complex cube root of unity.

∴ ω3 = 1 and 1 + ω + ω2 = 0

Also, 1 + ω2 = −ω, 1 + ω = −ω2 and ω + ω2 = −1

L.H.S. = `(a + bomega + comega^2)/(c + aomega + bomega^2)`

= `(aomega^3 + bomega^4  + comega^2)/(c + aomega + bomega^2)     ...[∵ omega^3 = 1, omega^4 = omega]`

= `(omega^2(c + aomega + bomega^2))/(c + aomega + bomega^2)`

= ω2

= R.H.S.

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पाठ 3: Complex Numbers - EXERCISE 3.3 [पृष्ठ ४२]

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