मराठी

If I = [ 1 0 0 1 ] , J = [ 0 1 − 1 0 ] a N D B = [ Cos θ Sin θ − Sin θ Cos θ ] Then B Equals )

Advertisements
Advertisements

प्रश्न

If \[I = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}, J = \begin{bmatrix}0 & 1 \\ - 1 & 0\end{bmatrix} and B = \begin{bmatrix}\cos \theta & \sin \theta \\ - \sin \theta & \cos \theta\end{bmatrix}\] then B equals ) 

पर्याय

  • I cos θ + J sin θ

  • I sin θ + J cos θ

  • I cos θ − J sin θ

  • I cos θ + J sin θ

MCQ
Advertisements

उत्तर

I cos θ + J sin θ

\[Here, \]

\[I \cos \theta + J \sin \theta\]

\[ = \begin{bmatrix}1 & 0 \\ 0 & 1\end{bmatrix}\cos \theta + \begin{bmatrix}0 & 1 \\ - 1 & 0\end{bmatrix}\sin \theta\]

\[ = \begin{bmatrix}\cos \theta & 0 \\ 0 & \cos \theta\end{bmatrix} + \begin{bmatrix}0 & \sin \theta \\ - \sin \theta & 0\end{bmatrix}\]

\[ = \begin{bmatrix}\cos \theta & \sin \theta \\ - \sin \theta & \cos \theta\end{bmatrix} = B\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Algebra of Matrices - Exercise 5.7 [पृष्ठ ६८]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 4 Algebra of Matrices
Exercise 5.7 | Q 30 | पृष्ठ ६८
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×