Advertisements
Advertisements
प्रश्न
If a + b + c = 0, then write the value of \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab}\]
Advertisements
उत्तर
We have to find the value of `a^2/(bc) + b^2/(ca) +c^2/(ab)`
Given `a+b+c = 0`
Using identity `a^3 +b^3 +c^3 - 3abc = (a+b+c) (a^2 +b^2 +c^2 - ab - bc - ca)`
Put `a+b +c = 0`
`a^3 +b^3 +c^3 - 3abc = (0)(a^2 +b^2 +c^2 - ab - bc - ca)`
`a^3 +b^3 + c^3 - 3abc = 0`
`a^3 +b^3 + c^3 = 3abc `
`a^3/(abc) + b^3/(abc) + c^3/(abc) = 3`
`(a xx axx a)/(abc) +(b xx bxx b)/(abc) +(c xx cxx c)/(abc) =3`
`a^2/bc +b^2/ac +c^2 /ab=3`
Hence the value of `a^2/(bc) + b^2/(ac) +c^2/(ab)` is 3.
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(3x + 4) (3x – 5)
Expand the following, using suitable identity:
`[1/4a-1/2b+1]^2`
Evaluate the following using suitable identity:
(998)3
Factorise the following:
8a3 + b3 + 12a2b + 6ab2
if `x^2 + 1/x^2 = 79` Find the value of `x + 1/x`
If 2x + 3y = 8 and xy = 2 find the value of `4x^2 + 9y^2`
Simplify the following product:
(x2 + x − 2)(x2 − x + 2)
Write in the expanded form: `(x/y + y/z + z/x)^2`
Simplify (2x + p - c)2 - (2x - p + c)2
If \[x - \frac{1}{x} = - 1\] find the value of \[x^2 + \frac{1}{x^2}\]
If a + b = 10 and ab = 21, find the value of a3 + b3
Evaluate the following:
(98)3
Evaluate of the following:
(99)3
If x = 3 and y = − 1, find the values of the following using in identify:
\[\left( \frac{x}{y} - \frac{y}{3} \right) \frac{x^2}{16} + \frac{xy}{12} + \frac{y^2}{9}\]
If \[x^3 + \frac{1}{x^3} = 110\], then \[x + \frac{1}{x} =\]
Use identities to evaluate : (998)2
Find the squares of the following:
9m - 2n
Find the squares of the following:
3p - 4q2
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" + (1)/"a"`
If 2x + 3y = 10 and xy = 5; find the value of 4x2 + 9y2
