Advertisements
Advertisements
प्रश्न
If a + b + c = 0, then write the value of \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab}\]
Advertisements
उत्तर
We have to find the value of `a^2/(bc) + b^2/(ca) +c^2/(ab)`
Given `a+b+c = 0`
Using identity `a^3 +b^3 +c^3 - 3abc = (a+b+c) (a^2 +b^2 +c^2 - ab - bc - ca)`
Put `a+b +c = 0`
`a^3 +b^3 +c^3 - 3abc = (0)(a^2 +b^2 +c^2 - ab - bc - ca)`
`a^3 +b^3 + c^3 - 3abc = 0`
`a^3 +b^3 + c^3 = 3abc `
`a^3/(abc) + b^3/(abc) + c^3/(abc) = 3`
`(a xx axx a)/(abc) +(b xx bxx b)/(abc) +(c xx cxx c)/(abc) =3`
`a^2/bc +b^2/ac +c^2 /ab=3`
Hence the value of `a^2/(bc) + b^2/(ac) +c^2/(ab)` is 3.
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
`(y^2+3/2)(y^2-3/2)`
Expand the following, using suitable identity:
(–2x + 5y – 3z)2
Simplify the following
`(7.83 + 7.83 - 1.17 xx 1.17)/6.66`
Simplify the following products:
`(x^3 - 3x^2 - x)(x^2 - 3x + 1)`
If \[x - \frac{1}{x} = - 1\] find the value of \[x^2 + \frac{1}{x^2}\]
Find the following product:
(3x + 2y) (9x2 − 6xy + 4y2)
Find the following product:
\[\left( \frac{x}{2} + 2y \right) \left( \frac{x^2}{4} - xy + 4 y^2 \right)\]
75 × 75 + 2 × 75 × 25 + 25 × 25 is equal to
Expand the following:
(3x + 4) (2x - 1)
Expand the following:
(a + 3b)2
Evaluate the following without multiplying:
(999)2
If a - b = 10 and ab = 11; find a + b.
If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :
`"a"^2 + (1)/"a"^2`
If `"r" - (1)/"r" = 4`; find : `"r"^4 + (1)/"r"^4`
Simplify:
(x + y - z)2 + (x - y + z)2
Simplify:
(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)
Factorise the following:
16x2 + 4y2 + 9z2 – 16xy – 12yz + 24xz
If a + b + c = 5 and ab + bc + ca = 10, then prove that a3 + b3 + c3 – 3abc = – 25.
