मराठी

If → a and → B Are Unit Vectors Inclined at an Angle θ, Then the Value of ∣ ∣ → a − → B ∣ ∣

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प्रश्न

If \[\vec{a} \text{ and } \vec{b}\] are unit vectors inclined at an angle θ, then the value of \[\left| \vec{a} - \vec{b} \right|\] 

पर्याय

  • (a) \[2 \sin\frac{\theta}{2}\] 

  • (b) 2 sin θ 

  • (c) \[2 \cos\frac{\theta}{2}\] 

  • (d) 2 cos θ 

MCQ
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उत्तर

(a) \[2 \sin\frac{\theta}{2}\]  

\[\vec{a} . \vec{b} = \left| \vec{a} \right| \left| \vec{b} \right| \cos \theta\]
\[ = 1 \times 1 \cos \theta(\text{ Because } \vec{a} \text{ and } \vec{b} \text{ are unit vectors })\]
\[ = \cos \theta . . . \left( i \right)\]
\[ \left| \vec{a} - \vec{b} \right|^2 = \left| \vec{a} \right|^2 + \left| \vec{b} \right|^2 - 2 \vec{a} . \vec{b} \]
\[ = 1 + 1 - 2 \cos \theta \left[ \text{ Using } \left( i \right) \right]\]
\[ = 2 - 2 \cos \theta \]
\[ = 2 \left( 1 - \cos \theta \right)\]
\[ = 2 \left( 2 \sin^2 \frac{\theta}{2} \right)\]
\[ = 4 \sin^2 \frac{\theta}{2}\]
\[ \therefore \left| \vec{a} - \vec{b} \right| = 2 \sin \frac{\theta}{2}\]

 

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पाठ 23: Scalar Or Dot Product - MCQ [पृष्ठ ५०]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 23 Scalar Or Dot Product
MCQ | Q 19 | पृष्ठ ५०
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