Advertisements
Advertisements
प्रश्न
If α and β are the zeroes of the polynomial x2 + x − 2, then find the value of `alpha/beta+beta/alpha`
Advertisements
उत्तर
Step 1: Use Sum and Product of Roots
Sum of roots: `alpha+beta = ("−coefficient of x")/("coefficient of" x^2)`
Product of roots: `alpha beta = ("constant term")/("coefficient of" x^2) = -2/1 = -2`
Step 2: Find `alpha/beta + beta/alpha`
`alpha/beta + beta/alpha = (alpha^2 + beta^2)/(alphabeta)`
α2 + β2 = (α + β)2 − 2αβ
Substituting known values:
α2 + β2 = (−1) 2 − 2(−2)
= 1 + 4 = 5
`alpha/beta + beta/alpha = 5/-2`
`= -5/2`
APPEARS IN
संबंधित प्रश्न
The graphs of y = p(x) are given in following figure, for some polynomials p(x). Find the number of zeroes of p(x).

One zero of the polynomial `3x^3+16x^2 +15x-18 is 2/3` . Find the other zeros of the polynomial.
If f(x) =`x^3-3x+5x-3` is divided by g(x)=`x^2-2`
Find ∝ , β are the zeros of polynomial ∝ +β= 6 and ∝β 4 then write the polynomial.
If one zero of the quadratic polynomial `kx^2 + 3x + k is 2`, then find the value of k.
Find the value of k such that the polynomial x2 − (k + 6)x + 2(2k −1) has sum of its zeros equal to half of their product.
A quadratic polynomial, whose zeroes are -3 and 4, is ______.
The number of polynomials having zeroes as -2 and 5 is ______.
A polynomial of degree n has ______.
If the zeroes of the quadratic polynomial ax2 + bx + c, c ≠ 0 are equal, then ______.
