Question

If AB, AC, PQ are tangents in Fig. and AB = 5 cm find the perimeter of ΔAPQ.

Answer 1

Perimeter of ΔAPQ, (P) = AP + AQ + PQ

= AP + AQ + (PX + QX)

We know that

The two tangents drawn from external point to the circle are equal in length from point A,

AB = AC = 5 cm

From point P, PX = PB

From point Q, QX = QC

Perimeter (P) = AP + AQ + (PB + QC)

= (AP + PB) + (AQ + QC)

= AB + AC = 5 + 5

= 10 cms.