मराठी

If a + b + c = 0, then a^3 + b^3 + c^3 is equal to ______.

Advertisements
Advertisements

प्रश्न

If a + b + c = 0, then a3 + b3 + c3 is equal to ______.

पर्याय

  • 0

  • abc

  • 3abc

  • 2abc

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

If a + b + c = 0, then a3 + b3 + c3 is equal to 3abc.

Explanation:

We know that,

a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)

As, a + b + c = 0,

So, a3 + b3 + c3 – 3abc = (0) (a2 + b2 + c2 – ab – bc – ca) = 0

Hence, a3 + b3 + c3 = 3abc.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Polynomials - Exercise 2.1 [पृष्ठ १६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 9
पाठ 2 Polynomials
Exercise 2.1 | Q 21. | पृष्ठ १६
बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 3 Expansions
MULTIPLE CHOICE QUESTIONS | Q 6. | पृष्ठ ३८
नूतन Mathematics [English] Class 9 ICSE
पाठ 3 Expansions
Exercise 3C | Q 8. | पृष्ठ ७४

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Expand the following, using suitable identity:

`[1/4a-1/2b+1]^2`


Factorise the following:

8a3 + b3 + 12a2b + 6ab2


If x + y + z = 0, show that x3 + y3 + z3 = 3xyz.


Simplify `(x^2 + y^2 - z)^2 - (x^2 - y^2 + z^2)^2`


Simplify the following expressions:

`(x + y - 2z)^2 - x^2 - y^2 - 3z^2 +4xy`


If \[x - \frac{1}{x} = - 1\]  find the value of  \[x^2 + \frac{1}{x^2}\]


If \[x + \frac{1}{x} = 5\], find the value of \[x^3 + \frac{1}{x^3}\]


If \[x^2 + \frac{1}{x^2} = 98\] ,find the value of \[x^3 + \frac{1}{x^3}\]


Evaluate of the following:

933 − 1073


If \[x + \frac{1}{x} = 3\], calculate  \[x^2 + \frac{1}{x^2}, x^3 + \frac{1}{x^3}\] and \[x^4 + \frac{1}{x^4}\]


Find the following product:

\[\left( 3 + \frac{5}{x} \right) \left( 9 - \frac{15}{x} + \frac{25}{x^2} \right)\]


If x = −2 and y = 1, by using an identity find the value of the following

\[\left( 5y + \frac{15}{y} \right) \left( 25 y^2 - 75 + \frac{225}{y^2} \right)\]

If  \[x^4 + \frac{1}{x^4} = 194,\] then \[x^3 + \frac{1}{x^3} =\]


If \[\frac{a}{b} + \frac{b}{a} = 1\] then a3 + b3 =


Find the square of 2a + b.


Use identities to evaluate : (101)2


If a - `1/a`= 8 and  a ≠ 0 find :
(i) `a + 1/a   (ii)  a^2 - 1/a^2`


Use the direct method to evaluate the following products:

(a – 8) (a + 2)


Use the direct method to evaluate :
(0.5−2a) (0.5+2a)


Evaluate: (5xy − 7) (7xy + 9) 


Evaluate: `(4/7"a"+3/4"b")(4/7"a"-3/4"b")`


Expand the following:
(x - 5) (x - 4)


Expand the following:
(3x + 4) (2x - 1)


Expand the following:
(a + 3b)2


Simplify by using formula :
(2x + 3y) (2x - 3y)


Simplify by using formula :
(1 + a) (1 - a) (1 + a2)


Simplify by using formula :

`("a" + 2/"a" - 1) ("a" - 2/"a" - 1)`


If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"  - (1)/"a"`


Simplify:
(x + 2y + 3z)(x2 + 4y2 + 9z2 - 2xy - 6yz - 3zx)


Factorise the following:

9x2 + 4y2 + 16z2 + 12xy – 16yz – 24xz


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×