Advertisements
Advertisements
प्रश्न
If 3ax + 2b2 = 3bx + 2a2, then express x in terms of a and b. Also, express the result in the simplest form.
Advertisements
उत्तर
3ax + 2b2 = 3bx + 2a2
⇒ 3ax - 3bx = 2a2 - 2b2
⇒ x(3a - 3b) = 2a2 - 2b2
⇒ x = `(2"a"^2 - 2"b"^2)/(3"a" - 3"b")`
⇒ x = `(2("a"^2 - "b"^2))/(3("a"- "b")`
⇒ x = `(2("a" + "b")("a" - "b"))/(3("a" - "b")`
⇒ x = `(2("a" + "b"))/(3)` ....(∵ a ≠ b)
APPEARS IN
संबंधित प्रश्न
The volume V, of a cone is equal to one third of π times the cube of the radius. Find a formula for it.
Make a the subject of formula S = `("a"("r"^"n" - 1))/("r" - 1)`
Given: mx + ny = p and y = ax + b. Find x in terms of m, n, p, a and b.
If V = pr2h and S = 2pr2 + 2prh, then express V in terms of S, p and r.
If b = `(2"a")/("a" - 2)`, and c = `(4"b" - 3)/(3"b" + 4)`, then express c in terms of a.
Make x the subject of the formula a = `1 - (2"b")/("cx" - "b")`. Find x, when a = 5, b = 12 and
Make h the subject of the formula K = `sqrt("hg"/"d"^2 - "a"^2`. Find h, when k = -2, a = -3, d = 8 and g = 32.
Make y the subject of the formula `x/"a" + y/"b" `= 1. Find y, when a = 2, b = 8 and x = 5.
The total energy E possess by a body of Mass 'm', moving with a velocity 'v' at a height 'h' is given by: E = `(1)/(2) "m" "u"^2 + "mgh"`. Find m, if v = 2, g = 10, h = 5 and E = 104.
"Area A oof a circular ring formed by 2 concentric circles is equal to the product of pie and the difference of the square of the bigger radius R and the square of the bigger radius R and the square of the smaller radius r. Express the above statement as a formula. Make r the subject of the formula and find r, when A = 88 sq cm and R = 8cm.
