Advertisements
Advertisements
प्रश्न
If 3 is a root of the quadratic equation x2 – px + 3 = 0, then p is equal to ______.
पर्याय
4
3
5
2
Advertisements
उत्तर
If 3 is a root of the quadratic equation x2 – px + 3 = 0, then p is equal to 4.
Explanation:
x = 3 is a root of the equation
x2 – px + 3 = 0 ...(i)
Then x = 3 will satisfy equation (i)
∴ (3)2 – 3p + 3 = 0
9 – 3p + 3 = 0
3p = 12
`\implies` p = `12/3`
`\implies` p = 4
APPEARS IN
संबंधित प्रश्न
Find the values of k for the following quadratic equation, so that they have two equal roots.
2x2 + kx + 3 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
x2 - 2kx + 7k - 12 = 0
Find the value of the discriminant in the following quadratic equation:
x2 +2x-2=0
Find, using the quadratic formula, the roots of the following quadratic equations, if they exist
x2 + 4x + 5 = 0
Find if x = – 1 is a root of the equation 2x² – 3x + 1 = 0.
48x² – 13x -1 = 0
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
3x2 + 2x - 1 = 0
Find the discriminant of the following equations and hence find the nature of roots: 16x2 - 40x + 25 = 0
Find the nature of the roots of the following quadratic equations: `x^2 - (1)/(2)x - (1)/(2)` = 0
The roots of equation (q – r)x2 + (r – p)x + (p – q) = 0 are equal.
Prove that 2q = p + r; i.e., p, q, and r are in A.P.
