Question

If 18 g of glucose are present in 1000 g of solvent, the solution is said to be ______.

पर्याय

• 1 molar

• 0.1 molar

• 0.5 molal

• 0.1 molal

Answer 1

If 18 g of glucose are present in 1000 g of solvent, the solution is said to be 0.1 molal.

Explanation:

Given: Mass of glucose = 18 g

Molar mass of glucose = 180 g/mol

Moles of glucose = `18/180` = 0.1 mol

Mass of solvent = 1000 g = 1 kg

Molality (m) = `"moles of solute"/"mass of solvent in kg"`

m = `0.1/1`

m = 0.1 mol/kg