Question

(i) The sum of two numbers is 40 and their difference is 8. The numbers will be 24 and 16.

(ii) If x + 3y = 10 and x + y = 4 then x = 2.

पर्याय

• Only (i)

• Only (ii)

• Both (i) and (ii)

• Neither (i) nor (ii)

Answer 1

Only (i)

Explanation:

(i) The sum of two numbers is 40 and their difference is 8.

Let the two numbers be x and y.

From the equations:

x + y = 40

x – y = 8

Adding both,

2x = 48

⇒ x = 24 

Subtracting,

2y = 32

⇒ y = 16

So, the numbers are indeed 24 and 16, making statement (i) true.

(ii) If x + 3y = 10 and x + y = 4, then subtracting second equation from first:

(x + 3y) – (x + y) = 10 – 4

⇒ 2y = 6

⇒ y = 3

Using y = 3 in x + y = 4:

x + 3 = 4

⇒ x = 1

So, x ≠ 2, making statement (ii) false.