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प्रश्न
How will the action of dilute hydrochloric acid enable you to distinguish between sodium carbonate and sodium sulphite?
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उत्तर
Sodium carbonate treated with dil. HCl results in the formation of sodium chloride with the liberation of carbon dioxide gas.
\[\ce{Na2CO3 + 2HCl ⟶ 2NaCl + H2O + CO2 ↑}\]
Sodium sulphite treated with dil. HCl results in the formation of sodium chloride with the liberation of sulphur dioxide gas.
\[\ce{Na2SO3 + 2HCl ⟶ 2NaCl + H2O + SO2 ↑}\]
संबंधित प्रश्न
Potassium sulfite on reacting with hydrochloric acid releases _______ gas. (Cl2, SO2, H2S)
State one relevant observation for the following
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Write a balanced equation for the action of dilute hydrochloric acid on sodium sulphide.
Name the gas that is produced in the given case:
An action of dilute hydrochloride acid on sodium sulphide.
Explain why anhydrous HCl is a poor conductor while aqueous HCl is an excellent conductor.
Write an equation for the reaction of hydrochloric acid on caustic soda solution.
Give reason for the following:
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Hint : Cl2 + H2O ⟶ HCl +HClO
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- Write the equation for the reaction which takes place in question (a).
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When barium chloride solution is added to salt solution E a white precipitate insoluble in dilute hydrochloric acid is obtained
Write the balanced equation for the reaction of dilute hydrochloric acid with the following:
Iron
