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प्रश्न
How is propene converted into 1- bromopropane and 2 - bromopropane?
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उत्तर
The addition of hydrogen halide to an unsymmetrical alkene gives two products.
Propene on reaction with hydrogen bromide forms 80% 2-bromopropane (isopropyl bromide) and 20% 1-bromopropane (n-propyl bromide).
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संबंधित प्रश्न
The preparation of alkyl fluoride from alkyl chloride, in presence of metallic fluorides is known as ______________.
What is the action of bromine in alkaline medium on
i. CH3CH2NO2
ii. 
The synthesis of alkyl fluorides is best accomplished by ____________.
The catalyst used in the preparation of an alkyl chloride by the action of dry HCl on alcohol is ____________.
Among the following, the most reactive towards alcoholic KOH is:
What is ‘A’ in the following reaction?
The order of reactivity of alcohols with halogen acids is ______.
(A) \[\ce{CH3CH2 - CH2 - OH}\]
(B) \[\begin{array}{cc}
\phantom{}\ce{CH3CH2 - CH - OH}\\
\phantom{...}\phantom{}|\\
\phantom{......}\ce{CH3}
\end{array}\]
(C) \[\begin{array}{cc}
\phantom{........}\ce{CH3}\\
\phantom{.....}\phantom{}|\\
\phantom{}\ce{CH3CH2 - C - OH}\\
\phantom{.....}\phantom{}|\\
\phantom{........}\ce{CH3}
\end{array}\]
Alkyl halides are prepared from alcohol by treating with ______.
(i) HCl + ZnCl2
(ii) Red P + Br
(iii) H2SO4 + KI
(iv) All the above
Alkyl fluorides are synthesised by heating an alkyl chloride/bromide in presence of ______ or ______.
(i) CaF2
(ii) CoF2
(ii) Hg2F2
(iv) NaF
Aryl chlorides and bromides can be easily prepared by electrophilic substitution of arenes with chlorine and bromine respectively in the presence of Lewis acid catalysts. But why does preparation of aryl iodides requires presence of an oxidising agent?
Write down the structure and IUPAC name for neo-pentylbromide.
Which of the following haloalkanes reacts with aqueous \[\ce{KOH}\] most easily? Explain giving reason.
Predict the major product formed when HCl is added to isobutylene. Explain the mechanism involved.
Match the structures given in Column I with the names in Column II.
| Column I | Column II | |
| (i) |  |
(a) 4-Bromopent-2-ene |
| (ii) |  |
(b) 4-Bromo-3-methylpent-2-ene |
| (iii) |  |
(c) 1-Bromo-2-methylbut-2-ene |
| (iv) |  |
(d) 1-Bromo-2-methylpent-2-ene |
Which of the following is the most stable free radical?
Which compound would undergo dehydrohalogenation with strong base to give the alkene shown below as the only alkene product?
CH3 – CH2CH = CH – CH3
Benzyl chloride (16H5CH2Cl) can be prepared from toluene by chlorination with
SN1 and SN2 product are same with
\[\begin{array}{cc}
\ce{Ph - CH - CH2 - CH2 ->[Zn - Cu][Δ] Product}\\
\phantom{..}|\phantom{......}|\phantom{....................}\\
\phantom{}\ce{Br}\phantom{....}\ce{Br}\phantom{..................}
\end{array}\]
Product of the above reaction is
Name the possible alkenes which will yield 1-chloro-1-methylcyclohexane on their reaction with HCl. Write the reactions involved.
Predict the reagent for carrying out the following transformations:
Ethanoic acid to 2-chloroethanoic acid
In the given conversion the compound A is:
The major product of the following reaction is:
Steps I and II are ______.
The major product of the following reaction is:
The number of stereoisomers are possible for a compound of the molecular formula \[\ce{CH3 - CH = CH - CH(OH) - Me}\] is ______.
