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प्रश्न
How much bigger is 5x2y2 – 18xy2 – 10x2y than –5x2 + 6x2y – 7xy?
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उत्तर
The required result,
(5x2y2 – 18xy2 – 10x2y) – (–5x2 + 6x2y – 7xy)
= 5x2y2 – 18xy2 – 10x2y + 5x2 + 6x2y – 7xy
= 5x2y2 – 18xy2 – 16x2y + 5x2 + 7xy
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संबंधित प्रश्न
Evaluate :
−7x2 + 18x2 + 3x2 − 5x2
Evaluate :
abx − 15abx − 10abx + 32abx
Evaluate :
3x2 + 5xy − 4y2 + x2 − 8xy − 5y2
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Subtract : a2 + ab + b2 from 4a2 − 3ab + 2b2
Take m2 + m + 4 from −m2 + 3m + 6 and the result from m2 + m + 1.
Subtract the sum of 5y2 + y – 3 and y2 – 3y + 7 from 6y2 + y – 2.
The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12. Find its third side.
The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z2. Find its perimeter.
