Advertisements
Advertisements
प्रश्न
How many tiles, each of area 400 cm2, will be needed to pave a footpath which is 2 m wide and surrounds a grass plot 25 m long and 13 m wide?
Advertisements
उत्तर
Area of grass = l × b
= 25 × 13
= 325 m2
The footpath is 2 m wide and surrounds the grass plot.
The new length of the plot, including the footpath, is:
Total length = 25 m + 2 m + 2 m
= 29 m
The new width of the plot, including the footpath, is:
Total width = 13 m + 2 m + 2 m
= 17 m
The total area is calculated using the new dimensions:
Total area = l × b
= 29 m × 17 m
= 493 m2
The area of the footpath is found by subtracting the area of the grass plot from the total area:
Area of footpath = Total area − Area of glass
= 493 m2 − 325 m2
= 168 m2
= 1680000 sq. cm
Total area = Number of tiles × Area covered by 1 tiles
⇒ 1680000 = Number of tiles × 400
⇒ Number of tiles = `(1680000)/(400)`
= 4200
Hence, the number of tiles = 4200.
APPEARS IN
संबंधित प्रश्न
The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
A rectangular plot of land measures 45 m x 30 m. A boundary wall of height 2.4 m is built all around the plot at a distance of 1 m from the plot. Find the area of the inner surface of the boundary wall.
ABCD is a square with each side 12 cm. P is a point on BC such that area of ΔABP: area of trapezium APCD = 1: 5. Find the length of CP.
The perimeter of a rhombus is 52 cm. If one diagonal is 24 cm; find:
(i) The length of its other diagonal,
(ii) Its area.
The length of a rectangular verandah is 3 m more than its breadth. The numerical value of its area is equal to the numerical value of its perimeter.
(i) Taking x as the breadth of the verandah, write an equation in x that represents the above statement
(ii) Solve the equation obtained in (i) above and hence find the dimensions of the verandah.
A triangle and a parallelogram have the same base and the same area. If the side of the triangle is 26 cm, 28 cm, and 30 cm and the parallelogram stands on the base 28 cm, find the height of the parallelogram.
Find the area of a quadrilateral field whose sides are 12m, 9m, 18m and 21m respectively and the angle between the first two sides is a right angle. Take the value of `sqrt(6)` as 2.5.
Vertices of given triangles are taken in order and their areas are provided aside. Find the value of ‘p’.
| Vertices | Area (sq.units) |
| (0, 0), (p, 8), (6, 2) | 20 |
In the following, find the value of ‘a’ for which the given points are collinear
(2, 3), (4, a) and (6, – 3)
When proving that a quadrilateral is a trapezium, it is necessary to show
