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प्रश्न
How many three-digit numbers can be formed using the digits 2, 3, 4, 5, 6 if digits can be repeated?
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उत्तर
A three-digit number is to be formed from the digits 2, 3, 4, 5, 6 where digits can be repeated.
Here, all the places can be filled in 5 ways each.
∴ By using the fundamental principle of multiplication, the total number of three-digit numbers = 5 × 5 × 5 = 125
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संबंधित प्रश्न
Evaluate: 6!
Evaluate: (8 – 6)!
Compute: 3! × 2!
Compute: `(9!)/(3! 6!)`
Write in terms of factorial:
6 × 7 × 8 × 9
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Find n, if `"n"/(8!) = 3/(6!) + 1/(4!)`
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
Find n, if (n + 1)! = 42 × (n – 1)!
Find n if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5:3
Find n, if: `((17 - "n")!)/((14 - "n")!)` = 5!
Find n, if: `((15 - "n")!)/((13 - "n")!)` = 12
Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24:1
Show that: `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`
Find the value of: `(8! + 5(4!))/(4! - 12)`
A hall has 12 lamps and every lamp can be switched on independently. Find the number of ways of illuminating the hall.
How many quadratic equations can be formed using numbers from 0, 2, 4, 5 as coefficient if a coefficient can be repeated in an equation.
A question paper has 6 questions. How many ways does a student have if he wants to solve at least one question?
