Advertisements
Advertisements
प्रश्न
Show that: `(9!)/(3!6!) + (9!)/(4!5!) = (10!)/(4!6!)`
Advertisements
उत्तर
L.H.S. = `(9!)/(3!6!) + (9!)/(4!5!)`
= `(9!)/(3!xx6 xx 5!) + (9!)/(4 xx 3! xx 5!)`
= `(9!)/(5!3!) [1/6 + 1/4]`
= `(9!)/(5! xx 3!)[(4 + 6)/(6xx4)]`
= `(9!xx10)/(6xx5!xx4xx3!)`
= `(10!)/(6!4!)`
= `(10!)/(4!6!)`
= R.H.S.
APPEARS IN
संबंधित प्रश्न
A teacher wants to select the class monitor in a class of 30 boys and 20 girls, in how many ways can the monitor be selected if the monitor must be a boy? What is the answer if the monitor must be a girl?
How many three-digit numbers can be formed using the digits 2, 3, 4, 5, 6 if digits can be repeated?
If numbers are formed using digits 2, 3, 4, 5, 6 without repetition, how many of them will exceed 400?
Compute: `(12/6)!`
Compute: (3 × 2)!
Compute: 3! × 2!
Compute: `(8!)/(6! - 4!)`
Write in terms of factorial:
5 × 6 × 7 × 8 × 9 × 10
Evaluate: `("n"!)/("r"!("n" - "r"!)` For n = 8, r = 6
Find n, if `"n"/(6!) = 4/(8!) + 3/(6!)`
Find n, if (n + 1)! = 42 × (n – 1)!
Find n if: `("n"!)/(3!("n" - 3)!) : ("n"!)/(5!("n" - 5)!)` = 5:3
Find n, if: `((15 - "n")!)/((13 - "n")!)` = 12
Find n, if: `((2"n")!)/(7!(2"n" - 7)!) : ("n"!)/(4!("n" - 4)!)` = 24:1
Find the value of: `(8! + 5(4!))/(4! - 12)`
Show that: `((2"n")!)/("n"!)` = 2n(2n – 1)(2n – 3)....5.3.1
A hall has 12 lamps and every lamp can be switched on independently. Find the number of ways of illuminating the hall.
