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प्रश्न
How is the critical angle related to the refractive index of a medium?
थोडक्यात उत्तर
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उत्तर
The relationship is `""_amu_m = 1/sin C`
When a light beam enters a liquid (m) from point A, it becomes ∠i = C with normal and emerges from the liquid in medium air, which is rarer, producing ∠r = 90°, or the ray BO becoming parallel to the liquid surface.
∴ `""_mmu_a = sin i/sin r = sin C/(sin 90°)`
Or `""_amu_m = (sin 90°)/sin C = 1/sin C`
∴ `""_amu_m = "R.I of medium" = 1/sin C`
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