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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Gold crystallises into face-centred cubic cells. The edge length of a unit cell is 4.08 × 10–8 cm. Calculate the density of gold. [Molar mass of gold = 197 g mol–1] - Chemistry

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प्रश्न

Gold crystallises into face-centred cubic cells. The edge length of a unit cell is 4.08 × 10–8 cm. Calculate the density of gold. [Molar mass of gold = 197 g mol–1]

When gold crystallizes, it forms face-centred cubic cell. The unit cell edge length is 408 pm. Calculate the density of gold. [Molar mass of gold = 197 g mole–1]

संख्यात्मक
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उत्तर

Given:

The edge length (a) of the unit cell = 408 pm = 4.08 × 10–8 cm

M = 197 g mol–1

It crystallises in Face-centred cubic cells.

Density (ρ) = `(nM)/(a^3N_A)`

Where n = Number of particles

For FCC, n = 4

M = Molar Mass

a = Edge length

NA = 6.022 × 1023

ρ = `(197 xx 4)/((4.08 xx 10^-8)^3 xx 6.022 xx 10^23)`

ρ = `788/(67.92 xx 10^-24 xx 6.022 × 10^23)`

ρ = `788/(408.99 xx 10^-1)`

ρ = 1.927 × 10−1

ρ = 19.27 g cm–3

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Cubic System
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2021-2022 (March) Set 1

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