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Given the following data, what will be the possible yield when the rainfall is 29. Details Rainfall Production Mean 25 40 units per acre Standard Deviation 3 6 - Business Mathematics and Statistics

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प्रश्न

Given the following data, what will be the possible yield when the rainfall is 29.

Details Rainfall Production
Mean 25`` 40 units per acre
Standard Deviation 3`` 6 units per acre

Coefficient of correlation between rainfall and production is 0.8.

बेरीज
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उत्तर

`bar"X"` = 25, σx = 3, `bar"Y"` = 40, σy = 6, r = 0.8

byx = `"r"(sigma_"y")/(sigma_"x") = 0.8 xx 6/3` = 1.6

`"Y" - bar"Y" = "b"_"yx"("X" - bar"X")`

Y − 40 = 1.6 (X − 25)

Y − 40 = 1.6X − (1.6)(25)

Y − 40 = 1.6X − 40

∴ Y = 1.6X

To find the yield when the rainfall is 29″

Put X = 29 in the above equation we get yield,

Y = 1.6 × 29 = 46.4 units/acre

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Regression Analysis
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Correlation and Regression Analysis - Exercise 9.2 [पृष्ठ २२७]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
पाठ 9 Correlation and Regression Analysis
Exercise 9.2 | Q 5 | पृष्ठ २२७

संबंधित प्रश्‍न

From the data given below:

Marks in Economics: 25 28 35 32 31 36 29 38 34 32
Marks in Statistics: 43 46 49 41 36 32 31 30 33 39

Find

  1. The two regression equations,
  2. The coefficient of correlation between marks in Economics and Statistics,
  3. The mostly likely marks in Statistics when the marks in Economics is 30.

Obtain the two regression lines from the following data N = 20, ∑X = 80, ∑Y = 40, ∑X2 = 1680, ∑Y2 = 320 and ∑XY = 480.


A survey was conducted to study the relationship between expenditure on accommodation (X) and expenditure on Food and Entertainment (Y) and the following results were obtained:

Details Mean SD
Expenditure on Accommodation (₹) 178 63.15
Expenditure on Food and Entertainment (₹) 47.8 22.98
Coefficient of Correlation 0.43

Write down the regression equation and estimate the expenditure on Food and Entertainment, if the expenditure on accommodation is ₹ 200.


The two regression lines were found to be 4X – 5Y + 33 = 0 and 20X – 9Y – 107 = 0. Find the mean values and coefficient of correlation between X and Y.


The regression coefficient of X on Y


When one regression coefficient is negative, the other would be


If the regression coefficient of Y on X is 2, then the regression coefficient of X on Y is


The lines of regression intersect at the point


X and Y are a pair of correlated variables. Ten observations of their values (X, Y) have the following results. ∑X = 55, ∑XY = 350, ∑X2 = 385, ∑Y = 55, Predict the value of y when the value of X is 6.


The following information is given.

Details X (in ₹) Y (in ₹)
Arithmetic Mean 6 8
Standard Deviation 5 `40/3`

Coefficient of correlation between X and Y is `8/15`. Find

  1. The regression Coefficient of Y on X
  2. The most likely value of Y when X = ₹ 100.

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