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Give reasons for need of Hybridization - Chemistry

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प्रश्न

Give reasons for need of Hybridization

थोडक्यात उत्तर
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उत्तर

The concept of hybridization was introduced because the valence bond theory failed to explain the following points:

  1. Valencies of certain elements:
    The maximum number of covalent bonds which an atom can form equals the number of unpaired electrons present in its valence shell. However, valence bond theory failed to explain how beryllium, boron, and carbon form two, three, and four covalent bonds respectively.
    a. Beryllium: The electronic configuration of beryllium is 1s2 2s2. The expected valency is zero (as there is no unpaired electron) but the observed valency is 2 as in BeCl2.
    b. Boron: The electronic configuration of boron is 1s2 2s2 \[\ce{2p^1_{{x}}}\]. The valency is expected to be 1 but it is 3 as in BF3.
    c. Carbon: The electronic configuration of carbon is 1s2 2s2 \[\ce{2p^1_{{x}}}\] \[\ce{2p^1_{{y}}}\]. The valency is expected to be 2, but the observed valency is 4 as in CH4.
  2. The shapes and geometry of certain molecules:
    The valence bond theory cannot explain shapes, geometries, and bond angles in certain molecules.
    e.g. a. Tetrahedral shape of a methane molecule.
    b. Bond angles in molecules like NH3 (107°18’) and H2O (104°35’).
    However, the valency of the above elements and the observe structural properties of the above molecules can be explained by the concept of hybridization. These are the reasons for need of the concept of hybridization.
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पाठ 5: Chemical Bonding - Exercises [पृष्ठ ७९]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
पाठ 5 Chemical Bonding
Exercises | Q 3. (E) | पृष्ठ ७९

संबंधित प्रश्‍न

Explain the formation of H2 molecule on the basis of valence bond theory.


Draw diagram for bonding in ethene with sp2 Hybridisation.


Draw an orbital diagram of Fluorine molecule


Distinguish between sigma and pi bond.


Give a reason for the sigma (σ) bond is stronger than the Pi (π) bond.


Identify the type of overlap present in H-F molecule. Explain diagrammatically.


Complete the following Table.

Molecule Type of Hybridization Type of bonds Geometry Bond angle
CH4 - 4C-H
4σ bonds
Tetrahedral -
NH3 sp3 3N-H
3σ bonds
1 lone pair
- -
H2O - - angular 104.5°
BF3 sp2 - - 120°
C2H4 - - - 120°
BeF2 - 2 Be-F Linear -
C2H2 sp (3σ+2π)
1C-C σ
2C-H σ
2C-C π
- -

Mention the steps involved in Hybridization.


The ratio of number of sigma (σ) and pi (л) bonds in 2- butynal is ______.


Which one of the following is the likely bond angles of sulphur tetrafluoride molecule?


According to Valence bond theory, a bond between two atoms is formed when ______.


In ClF3, NF3 and BF3 molecules the chlorine, nitrogen and boron atoms are ______.


When ones and three p orbitals hybridise,


Which of these represents the correct order of their increasing bond order.


Define σ – bond.


Which bond is stronger σ or π? Why?


Considering x-axis as the molecular axis which out of the following will form a sigma bond.

2px and 2py


Considering x-axis as the molecular axis which out of the following will form a sigma bond.

2px and 2pz


The number of sigma bonds in paracetamol is ____________.


The overlap of orbitals involved in the formation of C - Br bond in vinyl bromide is ______.


Why does type of overlap given in the following figure not result in bond formation?


Which of the following statements is INCORRECT according to the valence bond theory?


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