हिंदी

Give reasons for need of Hybridization - Chemistry

Advertisements
Advertisements

प्रश्न

Give reasons for need of Hybridization

संक्षेप में उत्तर
Advertisements

उत्तर

The concept of hybridization was introduced because the valence bond theory failed to explain the following points:

  1. Valencies of certain elements:
    The maximum number of covalent bonds which an atom can form equals the number of unpaired electrons present in its valence shell. However, valence bond theory failed to explain how beryllium, boron, and carbon form two, three, and four covalent bonds respectively.
    a. Beryllium: The electronic configuration of beryllium is 1s2 2s2. The expected valency is zero (as there is no unpaired electron) but the observed valency is 2 as in BeCl2.
    b. Boron: The electronic configuration of boron is 1s2 2s2 \[\ce{2p^1_{{x}}}\]. The valency is expected to be 1 but it is 3 as in BF3.
    c. Carbon: The electronic configuration of carbon is 1s2 2s2 \[\ce{2p^1_{{x}}}\] \[\ce{2p^1_{{y}}}\]. The valency is expected to be 2, but the observed valency is 4 as in CH4.
  2. The shapes and geometry of certain molecules:
    The valence bond theory cannot explain shapes, geometries, and bond angles in certain molecules.
    e.g. a. Tetrahedral shape of a methane molecule.
    b. Bond angles in molecules like NH3 (107°18’) and H2O (104°35’).
    However, the valency of the above elements and the observe structural properties of the above molecules can be explained by the concept of hybridization. These are the reasons for need of the concept of hybridization.
shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Chemical Bonding - Exercises [पृष्ठ ७९]

APPEARS IN

बालभारती Chemistry [English] Standard 11 Maharashtra State Board
अध्याय 5 Chemical Bonding
Exercises | Q 3. (E) | पृष्ठ ७९

संबंधित प्रश्न

Explain the formation of H2 molecule on the basis of valence bond theory.


Draw diagram for bonding in ethene with sp2 Hybridisation.


Distinguish between sigma and pi bond.


Give a reason for carbon is tetravalent in nature.


Identify the type of overlap present in F2. Explain diagrammatically.


Identify the type of overlap present in H-F molecule. Explain diagrammatically.


Complete the following Table.

Molecule Type of Hybridization Type of bonds Geometry Bond angle
CH4 - 4C-H
4σ bonds
Tetrahedral -
NH3 sp3 3N-H
3σ bonds
1 lone pair
- -
H2O - - angular 104.5°
BF3 sp2 - - 120°
C2H4 - - - 120°
BeF2 - 2 Be-F Linear -
C2H2 sp (3σ+2π)
1C-C σ
2C-H σ
2C-C π
- -

Which one of the following is the likely bond angles of sulphur tetrafluoride molecule?


In ClF3, NF3 and BF3 molecules the chlorine, nitrogen and boron atoms are ______.


When ones and three p orbitals hybridise,


Which of these represents the correct order of their increasing bond order.


The correct order of O – O bond length in hydrogen peroxide, ozone and oxygen is


Define σ – bond.


What is a pi - bond?


Considering x-axis as the molecular axis which out of the following will form a sigma bond.

1s and 2py


Considering x-axis as the molecular axis which out of the following will form a sigma bond.

2px and 2py


Considering x-axis as the molecular axis which out of the following will form a sigma bond.

2px and 2pz


Considering x-axis as the molecular axis which out of the following will form a sigma bond.

1s and 2pz


The number of sigma bonds in paracetamol is ____________.


The overlap of orbitals involved in the formation of C - Br bond in vinyl bromide is ______.


Briefly describe the valence bond theory of covalent bond formation by taking an example of hydrogen. How can you interpret energy changes taking place in the formation of dihydrogen?


Match List-I with List-II.

  List-I   List-II
(A) PCl5 (i) Square pyramidal
(B) SF6 (ii) Trigonal planar
(C) BrF5 (iii) Octahedral
(D) BF3 (iv) Trigonal bipyramidal

Choose the correct answer from the options given below.


The \[\ce{H - N - H}\] bond angle in ammonia molecule is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×