Advertisements
Advertisements
प्रश्न
Give possible expression for the length and breadth of the following rectangle, in which their area are given:
| Area : 25a2 – 35a + 12 |
Advertisements
उत्तर
Area = Length × Breadth
The expression given for the area of the rectangle has to be factorised. One of its factors will be its length and the other will be its breadth.
Area of a rectangle = (Length) × (Breadth)
25a2 – 35a + 12 = 25a2 – 15a − 20a + 12
= 5a(5a – 4) – 3(5a – 4)
= (5a – 4)(5a – 3)
Possible expression for length = 5a – 4
Possible expression for breadth = 5a – 3
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
`(y^2+3/2)(y^2-3/2)`
Write the following cube in expanded form:
`[x-2/3y]^3`
Evaluate the following using suitable identity:
(998)3
If 9x2 + 25y2 = 181 and xy = −6, find the value of 3x + 5y
Simplify the expression:
`(x + y + z)^2 + (x + y/2 + 2/3)^2 - (x/2 + y/3 + z/4)^2`
Find the following product:
If x = −2 and y = 1, by using an identity find the value of the following
If x + y + z = 8 and xy +yz +zx = 20, find the value of x3 + y3 + z3 −3xyz
If \[x + \frac{1}{x} = 2\], then \[x^3 + \frac{1}{x^3} =\]
If \[x^2 + \frac{1}{x^2} = 102\], then \[x - \frac{1}{x}\] =
If \[x^4 + \frac{1}{x^4} = 194,\] then \[x^3 + \frac{1}{x^3} =\]
If a2 + b2 + c2 − ab − bc − ca =0, then
If \[\frac{a}{b} + \frac{b}{a} = 1\] then a3 + b3 =
Use the direct method to evaluate the following products:
(x + 8)(x + 3)
Use the direct method to evaluate :
`("z"-2/3)("z"+2/3)`
Evaluate: 20.8 × 19.2
Expand the following:
(x - 5) (x - 4)
Expand the following:
(2p - 3q)2
If `"a" + (1)/"a" = 2`, then show that `"a"^2 + (1)/"a"^2 = "a"^3 + (1)/"a"^3 = "a"^4 + (1)/"a"^4`
Factorise the following:
25x2 + 16y2 + 4z2 – 40xy + 16yz – 20xz
