Question

From the equation

\[\ce{3Cu + 8HNO3 -> 3Cu(NO3)2 + 4H2O + 2NO}\]

(Atomic mass Cu = 64, H = 1, N = 14,O = 16)

Calculate the mass of copper needed to react with 63g of HNO₃.

Answer 1

Mol. Mass of 8HNO₃ = 8 × 63 = 504 g

For 504 g HNO₃, Cu required is = 192 g

So, for 63g HNO₃Cu required = `(192 xx 63)/504`

= 24g